-2y^2-16y+40=0

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Solution for -2y^2-16y+40=0 equation:


Simplifying
-2y2 + -16y + 40 = 0

Reorder the terms:
40 + -16y + -2y2 = 0

Solving
40 + -16y + -2y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2'.
2(20 + -8y + -1y2) = 0

Factor a trinomial.
2((2 + -1y)(10 + y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(2 + -1y)' equal to zero and attempt to solve: Simplifying 2 + -1y = 0 Solving 2 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1y = 0 + -2 -1y = 0 + -2 Combine like terms: 0 + -2 = -2 -1y = -2 Divide each side by '-1'. y = 2 Simplifying y = 2

Subproblem 2

Set the factor '(10 + y)' equal to zero and attempt to solve: Simplifying 10 + y = 0 Solving 10 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + y = 0 + -10 Combine like terms: 10 + -10 = 0 0 + y = 0 + -10 y = 0 + -10 Combine like terms: 0 + -10 = -10 y = -10 Simplifying y = -10

Solution

y = {2, -10}

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